Ag crystallises in fcc lattice. What is the total number of tetrahedral voids present in 540 ~g of Ag metal? (N_A= . Avagadro number; Ag atomic weight =108 ~g ~mol ⁻¹ )

Step-by-step solution

Ag crystallises in fcc lattice. Each unit cell contains 4 atoms and 8 tetrahedral voids. The mass of one Ag -atom = Atomic mass N_A = 108 ~g ~mol ⁻¹ N_A The mass of one unit cell will be =4 108 ~g ~mol ⁻¹ N_A Number of unit cells in 540 ~g of crystal = 540 ~g N_A 4 108 =1.25 N_A Number of tetrahedral voids in 1.25 unit cell =N_A 8 1.25=10 N_A