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AIIMS 2014
Exam
AIIMS
Year
2014
Subject
Chemistry
Chapter
Chemical Kinetics

AIIMS 2014 · Chemistry · Chemical Kinetics

For the reaction A_ (g) B_ (g) +C_ (g) , the rate constant is given...

For the reaction A(g)⟶B(g)+C(g)A_{(g)} \longrightarrow B_{(g)}+C_{(g)}, the rate constant is given as \left(P_i\right.isinitialpressureandis initial pressure andP_tispressureattimeis pressure at timet$ )

Options

  1. Ak=2.303tlog⁡PiPtk=\frac{2.303}{t} \log \frac{P_i}{P_t}
  2. Bk=\frac{2.303}{t} \log \frac{P_i}{\left(2 P_i-P_t\right)}
  3. Ck=2.303tlog⁡2Pi−PtPik=\frac{2.303}{t} \log \frac{2 P_i-P_t}{P_i}
  4. Dk=2.303tlog⁡Pi−Pt2Pik=\frac{2.303}{t} \log \frac{P_i-P_t}{2 P_i}

Correct answer

B. k=\frac{2.303}{t} \log \frac{P_i}{\left(2 P_i-P_t\right)}

Step-by-step solution

For the reaction, A(g)⟶B(g)+C(g)A_{(g)} \longrightarrow B_{(g)}+C_{(g)} t=0Pi00t(Pi−x)xx\begin{array}{llll} t=0 & P_i & 0 & 0 \\ t & \left(P_i-x\right) & x & x \end{array} Given: PiP_i is initial pressure at time, t=0andt=0 andP_tispressureattime′is pressure at time 't′.'.P_t=\left(P_i-x\right)+x+x=P_i+x x=P_t-P_iHere,Here,P_A=P_i-x \Rightarrow P_i-\left(P_t-P_i\right)PA=2Pi−PtP_A=2 P_i-P_t k=2.303tlog⁡PiPAk=\frac{2.303}{t} \log \frac{P_i}{P_A} k=2.303tlog⁡Pi(2Pi−Pt)k=\frac{2.303}{t} \log \frac{P_i}{\left(2 P_i-P_t\right)}
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