An element crystallising in fcc lattice has a density of 8.92 ~g ~cm ⁻³ and edge length of 3.61 10⁻⁸ ~cm . What is the atomic weight of element? (N=6.022 10²³ ~mol ⁻¹ )

Step-by-step solution

Given, d=8.92 ~g ~cm ⁻³ (Edge length) a=3.61 10⁻⁸ ~cm M= ? For fcc, Z=4d= Z M a^3 N 8.92= 4 M (3.61 10⁻⁸ )^3 6.022 10²³ M= 8.92 47.045 10⁻²⁴ 6.022 10⁻²³ 4 =63.178 u