KVPY2015ChemistryCarboxylic Acid Derivatives
In the reaction x , y and z are
Options
- Ax=M g , dry ether; y=C H₃ C l ; z=H₂ O
- Bx=M g , dry methanol; y=C O₂, z= dil. H C l
- Cx = Mg , dry ether; y = CO ₂ ; z = dil. HCl
- Dx= Mg , dry methanol; y = CH ₃ Cl , z = H ₂ O
Correct answer
C. x = Mg , dry ether; y = CO ₂ ; z = dil. HCl
Step-by-step solution
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