If (0.5 ~mol ) of a metal forms hexagonal close packed structure, the total number of voids, and tetrahedral voids respectively in mol are

Step-by-step solution

Number of moles of metal in close packed structure (=0.5 ~mol ) No. of atoms in 1 mole of mole (=N_A ) ( ) Number of atoms in (0.5 ~mol ) of metal (=0.5 6.022 10²³=3.011 10²³ ) Also, number of tetrahedral voids (=2 ) number of metal atoms in close packed structure ( ) Number of tetrahadral voids (=2 3.011 10²³ ) (=6.022 10²³ 1 ~mol ) Number of octahedral void (= ) number of metal atoms in close packed structure So, that number of octahedral voids (=3.011 10²³ ) (=0.5 ~mol ) Total number of voids ( aligned & = tetra