If the radius of an atom of an element which forms a body centered cubic unit cell is 173.2 pm , the volume of unit cell in cm ^3 is

Step-by-step solution

Given, Radius of an atom in body centered cubic (bcc) unit cell =173.2 pm . For bcc structure 3 a=4 r where, a= edge-length r= radius of atom and a^3=V (volume of cubic unit cell). a= 4 3 r or, a= 4 1.73 173.2 10⁻¹⁰ ~cm a=400 10⁻¹⁰ ~cm Therefore, aligned a^3 & =V= [400 10⁻¹⁰ ]^3 & =6,40,00,000 10⁻³⁰ & =6.4 10⁻²³ ~cm ^3 aligned Hence, 6.4 10⁻²³ ~cm ^3 is the correct answer.