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KVPY2014ChemistrySolid State

The radius of K ⁺ is 133 pm and that of Cl ^ - is 181 pm . The volume of the unit cell of KCl expressed in 10⁻²² cm ³ is

Options

  1. A0.31
  2. B1.21
  3. C2.48
  4. D6.28

Correct answer

C. 2.48

Step-by-step solution

V _ k+ + V _ Cl =133+181 KCl form FCC Lattice 2 (V_ V = a ^ K ⁺ + V _ Cl - )= a = edge length of unit cell

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