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AIIMS 2008
Exam
AIIMS
Year
2008
Subject
Chemistry
Chapter
Chemical Kinetics

AIIMS 2008 · Chemistry · Chemical Kinetics

For the reaction, (2 NO_2+F_2 arrow 2 NO_2 F), following mechanism...

For the reaction, (2 \mathrm{NO}_2+\mathrm{F}_2 \rightarrow 2 \mathrm{NO}_2 \mathrm{ F}), following mechanism has been provided. $$\begin{aligned} & \mathrm{NO}_2+\mathrm{F}_2 \stackrel{\text{ Slow }}{\longrightarrow} \mathrm{NO}_2 \mathrm{ F}+\mathrm{F} \\ & \mathrm{NO}_2+\mathrm{F} \stackrel{\text{ Fast }}{\longrightarrow} \mathrm{NO}_2 \mathrm{ F} \end{aligned}$$ Thus, rate expression of the above reaction can be written as

Options

  1. A(r=k\left[\mathrm{NO}_2\right]_2\left[\mathrm{~F}_2\right])
  2. B(r=k\left[\mathrm{NO}_2\right]\left[\mathrm{F}_2\right])
  3. C(r=k\left[\mathrm{NO}_2\right])
  4. D(r=k\left[\mathrm{~F}_2\right])

Correct answer

B. (r=k\left[\mathrm{NO}_2\right]\left[\mathrm{F}_2\right])

Step-by-step solution

Slowest step of mechanism decides the rate expression. Thus rate =k[NO2][F2]=k\left[\mathrm{NO}_2\right]\left[\mathrm{F}_2\right].
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