KVPY2017PhysicsLaws of Motion
A uniform rope of total length l is at rest on a table with fraction f of its length hanging (see figure). If the coefficient of friction between the table and the chain is then
Options
- Af=
- Bf=1 /(1+ )
- Cf=1 /(1+1 / )
- Df=1 /( +1 / )
Correct answer
C. f=1 /(1+1 / )
Step-by-step solution
f _ r = N = M ^ g = ( M - M _ f ) g at equilibrium. f _ r = M ^ g array l M (1- f ) g = M _ F g (1- f )= f =( +1) f f = 1 (1+ 1 ) array