KVPY2017PhysicsOscillations
One end of a rod of length L is fixed to a point on the circumference of a wheel of radius R . The other end is sliding freely along a straight channel passing through the centre O of the wheel as shown in the figure below. The wheel is rotating with a constant angular velocity about O . Taking T = 2 the motion of the rod is
Options
- Asimple harmonic with a period of T
- Bsimple harmonic with a period of T / 2
- Cnot simple harmonic but periodic with a period of T
- Dnot simple harmonic but periodic with a period of T / 2
Correct answer
C. not simple harmonic but periodic with a period of T
Step-by-step solution
array l = R ²+ x ²- L ² 2 Rx x ²=2 Rx cosec + L ²- R ² array displacement of S.H. M. is in the form of x = A t + c Therefore it is not S. H. M. It is S. H. M. only which. It L = R . array l x ²=2 Rx x =2 R x =2 R t [ S.H. M.] array But period of this motion is T