KVPY2010PhysicsRay Optics
A narrow parallel beam of light falls on a glass sphere of radius R and refractive index at normal incidence. The distance of the image from the outer edge is given by-
Options
- AR (2- ) 2( -1)
- BR (2+ ) 2( -1)
- CR (2- ) 2( +1)
- DR (2+ ) 2( +1)
Correct answer
A. R (2- ) 2( -1)
Step-by-step solution
now V ₁ - 1 = -1 R V ₁= R -1 now 1 ~V _ f - - (2 R - V ₁ ) = 1- - R replace V ₁ by R -1 and ving for V _ f we get V _ f = R ( -2) 2( -1) First image is real and second is virtual.