Equal moles of NO ₂(g) and NO (g) are to be placed in a container to produce N ₂ O according, to the reaction, NO ₂+ NO ~N ₂ O + O ₂ ; K_C=0.914 How many moles of NO ₂ and NO be placed in the 5.0 L container to have an equilibrium concentration of N ₂ O to be 0.05 M ?

Step-by-step solution

Equilibrium concentration of N ₂ O = O ₂=0.05 M Let the equilibrium concentration of NO ₂ and NO bexM K_c=0.917= (0.05)^2 x^2 x=0.0522 M Initial concentrations of NO ₂ and NO were 0.05+x=0.1022 M each. Hence, moles of each gas NO ₂ and NO taken initially =5 0.1022=0.511