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Manipal MET2010PhysicsCenter of Mass, Momentum and Collision

A bomb of mass 9 kg explodes into two parts. One part of mass 3 kg moves with velocity 16 ~m / s , then the KE of the other part is

Options

  1. A162 J
  2. B150 J
  3. C192 J
  4. D200 J

Correct answer

C. 192 J

Step-by-step solution

From the law of conservation of momentum 3 16+6 v=9 0 or v=-8 ~m / s v=8 ~m / s (numerically) Therefore, its kinetic energy K= 1 2 6 (8)^2=192 ~J

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