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Manipal MET2011PhysicsCenter of Mass, Momentum and Collision

In an explosion a body breaks up into pieces of unequal masses. In this case

Options

  1. Aboth parts will have numerically equal momentum
  2. Blighter part will have more momentum
  3. Cheavier part will have more momentum
  4. Dboth parts will have equal kinetic energy

Correct answer

A. both parts will have numerically equal momentum

Step-by-step solution

From law of conservation of linear momentum i.e., final momentum = initial momentum m₁ v₁+m₂ v₂=0 ...i(i) where m₁ and m₂ are masses of pieces. (initial momentum is zero because body is stationary) From Eq. (i), m₁ v₁=-m₂ v₂ So, numerical value of momentum of both pieces will be equal.

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