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Manipal MET2011PhysicsDual Nature of Matter

The rest energy of an electron is 0.511 MeV . The electron is accelerated from rest to a velocity 0.5 c . The change in its energy will be

Options

  1. A0.026 MeV
  2. B0.051 MeV
  3. C0.079 MeV
  4. D0.105 MeV

Correct answer

C. 0.079 MeV

Step-by-step solution

According to Einstein's equation relation between rest energy and moving energy is E=E₀ (1- v^2 c^2 )^ -1 / 2 Given, v=0.5 c E=E₀ (1- (0.5 c)^2 c^2 )^ -1 / 2 aligned E & =E₀(1-0.25)^ -1 / 2 & = E₀ 0.75 aligned Change in energy E=E-E₀ aligned & = E₀ 0.75 -E₀ & =E₀ ( 1 0.75 -1 ) & =0.511 ( 1 0.75 -1 ) & =0.079 MeV aligned

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