In a neon discharge tube 2.9 10¹⁸ Ne ⁺ ions move to the right each second while 1.2 10¹⁸ electrons move to the left per second, electrons charge is 1.6 10⁻¹⁹ C . The current in the discharge tube is

Step-by-step solution

Direction of current is opposite to the direction of flow of electron and in the same direction of positive ion. Total current I=I_ Ne +I_ electron aligned & = (2.9 10¹⁸+1.2 10¹⁸ ) e & =4.1 10¹⁸ 1.6 10⁻¹⁹ & =0.66 ~A aligned Direction of current will be the direction of flow of Ne ⁺ ion i. e. towards right.