Manipal MET2021PhysicsLaws of Motion
A simple spring has length L and force constant k . It is cut into two springs of lengths l₁ and L₂ such that l₁=n L₂ ( n= an integer). The force constant of spring of length l₁ is :
Options
- Ak(1+n)
- Bk n (1+n)
- Ck
- Dk (n+1)
Correct answer
B. k n (1+n)
Step-by-step solution
Since L₁+n L₂ where n is an integer, so the spring is made of (n+1) equal parts in length each of length I₂ | 1 k = (n+1) k^ or k^ =(n+1) k The spring of length l₁ (=n l₂ ) will be equivalent to n springs connected in series where spring constant k^ = k^ n = (n+1) k n