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Manipal MET2021PhysicsLaws of Motion

A simple spring has length L and force constant k . It is cut into two springs of lengths l₁ and L₂ such that l₁=n L₂ ( n= an integer). The force constant of spring of length l₁ is :

Options

  1. Ak(1+n)
  2. Bk n (1+n)
  3. Ck
  4. Dk (n+1)

Correct answer

B. k n (1+n)

Step-by-step solution

Since L₁+n L₂ where n is an integer, so the spring is made of (n+1) equal parts in length each of length I₂ | 1 k = (n+1) k^ or k^ =(n+1) k The spring of length l₁ (=n l₂ ) will be equivalent to n springs connected in series where spring constant k^ = k^ n = (n+1) k n

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