A fireman weighing 80 kg slides down a pole. If the resisting force of friction is 720 N , his acceleration would be : (take .g=10 ~m / s ^2 )

Step-by-step solution

Force of friction =720 ~N If a is the acceleration of fireman, sliding down the pole, then aligned m g-F & =m a a & = m g-F m & = (80 10-720) 80 & =1 ~m / s ^2 aligned