A man weighing 100 kg slides down a light rope with an acceleration of 1.8 ~ms ⁻² . If g=9.8 ~ms ⁻² , the tension of the rope is

Step-by-step solution

The resultant of tension and weight given acceleration to the man, hence m g-T=m a T=m g-m a=m(g-a) Given, m=100 ~kg , aligned & g=9.8 ~m / s ^2, a=1.8 ~ms ⁻² . & T=100(9.8-1.8)=800 ~N aligned