Two unequal masses are connected on two sides of a light string passing over a light and smooth pulley as shown in the figure. The system is released from the rest. The larger mass is stoped for a moment, is after the system is set into motion. The time elapsed before the string is tight again is

Step-by-step solution

Net pulling force =2 g-1 g=10 ~N Mass being pulled =2+1=3 ~kg Acceleration of the system is a= 10 3 ~m / s ^2 Velocity of both the blocks at t=1 ~s will be v₀=a t= ( 10 3 )(1)= 10 3 ~m / s Now at this moment, velocity of 2 kg becomes zero, while that of 1 kg block is 10 ~m / s upwards. Hence, string becomes tight again when displacement of 1 kg block = displacement of 2 kg block. array ll & v₀ t- 1 2 g t^2= 1 2 g t^2 & t= v₀ g = 10 3 10 = 1 3 ~s array