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Manipal MET2013PhysicsLaws of Motion

A car is moving along a straight horizontal road with a speed v₀ . If the coefficient of friction between the tyres and the road is , the shortest distance in which the car be stopped is

Options

  1. Av₀^2
  2. B( v₀ _g )^2
  3. Cv₀^2 _g
  4. Dv₀^2 2 _g

Correct answer

D. v₀^2 2 _g

Step-by-step solution

Work done against frictional force equals the kinetic energy of the body. when a body of mass m , moves with velocity v , it has kinetic energy k= 1 2 m v^2 , this energy is utilized in doing work against the frictional force between the tyres of the car and road. kinetic energy = work done against friction force 1 2 mv^2= mgs where s is the distance in which the car is stopped and is coefficient of kinetic friction. Given V=V₀s= v₀^2 2 g

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