Manipal MET2020PhysicsMagnetic Properties of Matter
The horizontal component of earth's magnetic field at a place is 0.4 10^4 ~T . If the angle of dip is 45^ the value of total intensity of earth's magnetic field is
Options
- A0.5 10⁻⁴ ~T
- B0.4 10⁻⁴ ~T
- C0.5 10⁻⁶ T
- D0.4 10⁻⁶ T
Correct answer
A. 0.5 10⁻⁴ ~T
Step-by-step solution
Vertical component of earth's magnetic field is B_V=B_H where, B_H= horizontal component of earth's magnetic field = angle of dip. Total intensity of earth's maanetic field aligned B & = B_H^2+B_V^2 & = B_H^2+B_H^2 [ = 45^ =1 ] & = 2 B_H & =1.44 0.4 10⁻⁴ ~T & =5.656 10⁻⁵ ~T & =0.5 10⁻⁴ ~T aligned