Order of magnitude of density of uranium nuclus is ( m_p=1.6 10⁻²⁷ ~kg )

Step-by-step solution

Radius of a nucleus is given by aligned R & =R₀ A^ 1 / 3 ( where, R₀=1.25 10⁻¹⁵ ~m ) & =1.25 10⁻¹⁵ A^ 1 / 3 ~m aligned Here, A is the mass number and mass of the uranium nucleus will be aligned m & A m_p, m_p= mass of proton & =A (1.67 10⁻²⁷ ~kg ) aligned Density = Mass Volume = m 4 3 R^3 = A (1.67 10⁻²⁷ ) A 4 3 22 7 (1.25 10⁻¹⁵ )^3 =2 10¹⁷ ~kg / m ^3 order is 10¹⁷