Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Manipal MET2012PhysicsNuclear Physics

A nucleus X initially at rest, undergoes alpha decay according to the equation 92 X^A _Z Y²²⁸+ Then, the value of A and Z are

Options

  1. A94,230
  2. B232,90
  3. C190,32
  4. D230,94

Correct answer

B. 232,90

Step-by-step solution

The decay equation is ₉₂ X^A _Z Y²²⁸+ -particle is nucleus of ₂ He ^4 gathered ₉₂ X^A _Z Y²²⁸+ ₂ He ^4 A=228+4=232 Z=92-2=90 gathered

Practice Nuclear Physics on Quantrex Academy →

More from Nuclear Physics

The main function of cadmium used in the nuclear reactor is: 2026The atomic mass of an element ₁₀X²⁰ is 19.98170 amu. The binding energy per nucleon of that element is: [given mass of neutron = 1.00867 amu and mass of proton = 1.00783 amu and 1a 2026If the ratio of the nuclear radii of two atoms is 2:3 then the ratio of their mass numbers is: 2026Two deuterons are fused to form one alpha particle. If binding energy per nucleon of deuterium is 1.05 MeV and that of alpha particle is 7 MeV, what is the energy released in the f 2026A nucleus of uranium-235 absorbs a slow neutron and undergoes nuclear fission according to the reaction: ²³⁵₉₂U + ¹₀n ¹⁴¹₅₆Ba + ⁹²₃₆Kr + 3 ¹₀n + Q If the average energy released pe 2026A mercury-198 nucleus is bombarded by a neutron, which causes a nuclear reaction ¹₀n + ¹⁹⁸₈₀Hg ¹⁹⁷₇₉Au + X What is the unknown product particle X? 2026The three numbers: (number of protons, number of neutrons, the radius) characterize a nucleus. What is the value of r₁ r₂ for two nuclei characterized by (1, 0, r₁) and (4, 4, r₂) 2026If the binding energy per nucleon of deuteron ( ₁ H ^2 ) is 1.15 MeV and an -particle has a binding energy of 7.1 MeV per nucleon, then the energy released per nucleon in the given 2025 Full Nuclear Physics list All Manipal MET PYQs