Manipal MET2019PhysicsNuclear Physics
The nuclear reaction ₁ H ^1+ ₁ H ^1 ₂ He ^4 (mass of deuteron =2.0141 amu and of He =4.0024 amu ) is
Options
- Afusion reaction releasing 24 MeV energy
- Bfusion reaction absorbing 24 MeV energy
- Cfission reaction releasing 0.0258 MeV energy
- Dfission reaction absorbing 0.0258 MeV energy
Correct answer
A. fusion reaction releasing 24 MeV energy
Step-by-step solution
₁ H ^1+ ₁ H ^1 ₂ He ^4 Mass defect aligned m & =2 mass of 1₁ H ^1- mass of ₂ He ^4 & =2 2.0141-4.0024 & =0.0258 aligned aligned Energy released & = m 931 MeV & =0.0258 931=24 MeV aligned