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Manipal MET2020PhysicsOscillations

A particle, doing simple harmonic motion, at a distance 3 cm from mean position has acceleration 12 ~cm / s ^2 . What is its time period?

Options

  1. A0.5 s
  2. B1s
  3. C2 s
  4. D3.14 s

Correct answer

D. 3.14 s

Step-by-step solution

The time period of a particle executing SHM is T=2 x a =2 Displacement Acceleration =2 3 10⁻² 12 10⁻² =2 1 2 = =3.14 ~s

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