The two blocks of masses m₁ and m₂ are kept on a smooth horizontal table as shown in the figure. Block of mass m₁ but not m₂ is fastened to the spring. If now both the blocks are pushed to the left, so that the spring is compressed at a distance d . The amplitude of oscillation of block of mass m₁ after the system released, is

Step-by-step solution

Block of mass m₂ shoots off carrying some kinetic energy away from the system. To find its speed, potential energy of spring = maximum kinetic energy of blocks. k d^2 2 = (m₁+m₂ ) v^2 2 [ k= force constant of spring] v^2= k d^2 m₁+m₂ with m₁ along on the spring. Maximum potential energy = Maximum kinetic energy of m₂ array ll & 1 2 k A^2= 1 2 m₁ v^2 k A^2= k m₁ d^2 m₁+m₂ & A=d m₁ m₁+m₂ array