Two particles executes SHM of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions. Each time their displacement is half of their amplitude. The phase difference between them is

Step-by-step solution

Let two simple harmonic motions are y=a t and y=a ( t+ ) In the first case, a 2 =a t t= 1 2 t= 3 2 In the second case, a 2 =a ( t+ ) aligned & 1 2 =[ t + t ] & 1 2 = [ 1 2 + 3 2 ] & 1- = 3 & (1- )^2=3 ^2 & (1- )^2=3 (1- ^2 ) aligned On solving we get aligned & =+1 or = -1 2 & i.e., =0 or =120^ aligned