T₁ is the time period of simple pendulum. The point of suspension moves vertically upwards according to y=k t^2 , where k=1 ~m / s ^2 . New time period is T₂ , then T₁^2 T₂^2 =? (g=10 ~m / s ^2 )

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Quantrex Academy · Accepted Answer

Correct answer: B. 6 / 5

Acceleration of the point of suspension aligned a & = d^2 y d t^2 =2 k=2 ~m / s ^2 T & =2 L g_ eff T₁=2 L 10 and T₂=2 L 12 T₁^2 T₂^2 & = 6 5 aligned

T₁ is the time period of simple pendulum. The point of suspension moves vertically upwards according to y=k t^2 , where k=1 ~m / s ^2 . New time period is T₂ , then T₁^2 T₂^2 =? (g=10 ~m / s ^2 )

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