Manipal MET2013PhysicsOscillations
A simple pendulum has time period T₁ . The point of suspension is now moved upward according to the relation y=k t ^2 (k=1 ~ms ^2 ) where y is the vertical displacement. The time period now become T₂ . The ratio of T₁^2 T₂^2 is g=10 ~m / s ^2
Options
- A6 / 5
- B5/6
- C1
- D4 / 5
Correct answer
A. 6 / 5
Step-by-step solution
y=k t^2 aligned d^2 y d t^2 & =2 k a & =2 ~m / s ^2 T₁ & =2 l g T₂ & =2 l g+a_y T₁^2 T₂^2 & = g+a_y g & = 10+2 10 = 6 5 aligned