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Manipal MET2013PhysicsOscillations

For a particle executing simple harmonic motion, the kinetic energy k is given by, k=k₀ ^2 t . The maximum value of potential energy is

Options

  1. Ak₀
  2. Bzero
  3. Ck₀ / 2
  4. Dnot obtainable

Correct answer

A. k₀

Step-by-step solution

K=K₀= total energy As total energy remains conserved itself hence when U is maximum in SHM , K=0 i.e., E is also equal to U_ i.e., U_ =E=K₀

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