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Manipal MET2011PhysicsOscillations

The acceleration of a particle performing SHM is 12 ~cm / s ^2 at a distance of 3 cm from the mean position. Its time period is

Options

  1. A0.5 s
  2. B1.0 s
  3. C2.0 s
  4. D3.14 s

Correct answer

D. 3.14 s

Step-by-step solution

Acceleration a= ^2 y aligned a & = ( 2 T )^2 y T^2 & = 4 ^2 y a T & =2 y a & =2 3 12 T & =2 1 2 =3.14 ~s aligned T=2 1 2 =3.14 ~s

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