Manipal MET2011PhysicsOscillations
The acceleration of a particle performing SHM is 12 ~cm / s ^2 at a distance of 3 cm from the mean position. Its time period is
Options
- A0.5 s
- B1.0 s
- C2.0 s
- D3.14 s
Correct answer
D. 3.14 s
Step-by-step solution
Acceleration a= ^2 y aligned a & = ( 2 T )^2 y T^2 & = 4 ^2 y a T & =2 y a & =2 3 12 T & =2 1 2 =3.14 ~s aligned T=2 1 2 =3.14 ~s