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Manipal MET2020PhysicsOscillations

A mass m hanging from a spring is doing simple harmonic motion with frequency f . If the mass is increased by 4 times, then frequency will be

Options

  1. A2 f
  2. Bf / 2
  3. C4 f
  4. Df / 4

Correct answer

B. f / 2

Step-by-step solution

Frequency for a mass m executing SHM f= 1 2 k m ....(i) When the mass is increased by 4 times, then the new frequency f^ = 1 2 k 4 m = 1 2 1 2 k m = f 2

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