Manipal MET2017PhysicsRay Optics
A thin rod of length f 3 is placed along the optic axis of a concave mirror of focal length f , such that its image which is real and elongated just touches the rod, the magnification is
Options
- A1.5
- B2.5
- C3.5
- D4.5
Correct answer
A. 1.5
Step-by-step solution
u=P A=P C-A C=2 f- f 3 = 5 f 3 From mirror formula 1 f = 1 v + 1 u 1 v = 1 f - 1 u = 1 f - 3 5 f = 2 5 f Length of image C A^ =P A^ -P C= 5 f 2 -2 f= f 2 Magnification (m)= C A^ C A = f / 2 f / 3 =1.5