When a glass prism of refracting angle 60^ is immersed in a liquid its angle of minimum deviation is 30^ . The critical angle of glass with respect to the liquid medium is

Step-by-step solution

Given, A=60^ and _m=30^ So, = ( A+ _m 2 ) A 2 = ( 60^ +30^ 2 ) 60^ 2 = 45^ 30^ = 1 2 2= 2 2 2 2 = 2 2 2 = 2 We have, = 1 C or 2 = 1 C or C= ⁻¹ ( 1 2 )=45^