Manipal MET2021PhysicsRotational Motion
A uniform thin bar of mass 6 m and length 12 L is bent to make a regular hexagon. Its moment of inertia about an axis passing through the centre of mass and perpendicular to the plane of hexagon is :
Options
- A20 ~mL ^2
- B30 ~mL ^2
- C12 5 mL^2
- D6 ~mL ^2
Correct answer
A. 20 ~mL ^2
Step-by-step solution
Length of each side of hexagon =2 L and mass of each side =m Let O be the centre of mass of hexagon. Therefore, perpendicular distance of O from each side, r=L 60^ =L 3 The desired moment of inertia of hexagon about O is aligned I & =6 [I_ one side ]=6 [ m(2 L)^2 12 +m r^2 ] & =6 [ mL^2 3 +m(L 3 )^2 ] & =20 mL^2 aligned