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Manipal MET2013PhysicsRotational Motion

The moment of inertia of a disc of mass m and radius R about an axis, which is tangential to the circumference of the disc and parallel to its diameter is

Options

  1. A3 2 m R^2
  2. B2 3 m R^2
  3. C5 4 m R^2
  4. D4 5 m R^2

Correct answer

C. 5 4 m R^2

Step-by-step solution

Use parallel axis theorem, from the theorem of parallel axis, the moment of inertia ( / ) of a body about given axis is equal to its moment of inertia/about its diameter, plus the product of the mass M of the body and square of perpendicular distanće between the two axes. That is I=I_d+M R^2= 1 4 M R^2+M R^2= 5 4 M R^2

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