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Manipal MET2010PhysicsRotational Motion

A rod of length L and mass M is bent to form a semicircular ring as shown in figure. The moment of inertia about X Y is

Options

  1. A1 4 M L^2 ^2
  2. B2 M L^2 3 ^2
  3. CM L^2 2
  4. DM L^2 2

Correct answer

A. 1 4 M L^2 ^2

Step-by-step solution

Here, L= R or R= L Moment of inertia about X Y aligned & = 1 2 ( 1 2 M R^2 ) & = 1 4 M L^2 ^2 aligned

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