Identify the product 'B' in the following reaction Isopropyl cyanide SnCl ₂, HCl A H ₃ O ^+ B + NH ₄ Cl

Step-by-step solution

The given reaction is Stephen reduction. Isopropyl cyanide is CH ₃- CH ( CH ₃)- CN . When isopropyl cyanide is treated with SnCl ₂ and HCl , it undergoes reduction to form an imine hydrochloride intermediate (A). CH ₃- CH ( CH ₃)- CN + 2[ H ] + HCl SnCl ₂, HCl CH ₃- CH ( CH ₃)- CH = NH HCl (A) Acidic hydrolysis of the imine hydrochloride yields the corresponding aldehyde (B). CH ₃- CH ( CH ₃)- CH = NH HCl + H ₂ O H ₃ O ^+ CH ₃- CH ( CH ₃)- CHO + NH ₄ Cl The product B is CH ₃- CH ( CH ₃)- CHO , which is 2-methylprop