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MHT CET202616 April 2026Morning ShiftChemistryAldehydes and KetonesActual

An organic compound CH ₃ -CH=CH-CH ₂ -CHO is taken in two different containers A and B. Sample in A is treated with H ₂ / Ni forming new compound P. Sample in B is treated with LiAlH ₄ and hydrolyzed further forming new compound Q. Identify P and Q.

Options

  1. AP = Q = CH ₃ -CH=CH-CH ₂ -CH ₂ OH
  2. BP = Q = CH ₃( CH ₂)₃ CH ₂ OH
  3. CP = CH ₃( CH ₂)₃ CHO and Q = CH ₃( CH ₂)₃ CH ₂ OH
  4. DP = CH ₃( CH ₂)₃ CH ₂ OH and Q = CH ₃ -CH=CH-CH ₂ -CH ₂ OH

Correct answer

D. P = CH ₃( CH ₂)₃ CH ₂ OH and Q = CH ₃ -CH=CH-CH ₂ -CH ₂ OH

Step-by-step solution

The given organic compound is CH ₃ -CH=CH-CH ₂ -CHO . When treated with H ₂ in the presence of Ni catalyst, both the carbon-carbon double bond and the aldehyde group are reduced. The alkene is reduced to an alkane and the aldehyde is reduced to a primary alcohol. Thus, the product P is pentan-1-ol, which is CH ₃( CH ₂)₃ CH ₂ OH . When treated with LiAlH ₄ followed by hydrolysis, only the aldehyde group is reduced to a primary alcohol. LiAlH ₄ does not reduce isolated carbon-carbon double bonds. Thus, the double bon

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