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MHT CET202519 Apr 2025Evening ShiftChemistryAldehydes and KetonesActual

Identify the product ' B ' in the following sequence of ractions. Methyl magnesium bromide CdCl ₂ ~A CH ₃ COCl B

Options

  1. ADimethyl cadmium
  2. BPropanone
  3. CButanone
  4. DPropanal

Correct answer

B. Propanone

Step-by-step solution

Formation of Product A: Methyl magnesium bromide, CH₃MgBr , reacts with cadmium chloride, CdCl₂ , to form the dimethylcadmium compound via the reaction: 2 CH₃MgBr + CdCl₂ ( CH₃ )₂ Cd + 2 MgClBr This yields Product A as dimethylcadmium, ( CH₃ )₂ Cd . Formation of Product B: Dimethylcadmium then reacts with acetyl chloride, CH₃COCl , forming propanone (acetone) through: ( CH₃ )₂ Cd + 2 CH₃COCl 2 CH₃COCH₃ + CdCl₂ Thus, Product B is propanone ( CH₃COCH₃ ), corresponding to option B. The final answer is B .

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