MHT CET202526 Apr 2025Evening ShiftChemistryCarboxylic Acid DerivativesActual
Identify the product formed in the following reaction. CH ₃ CH ₂ Mg Br [ ii) dil. HCl ] i) Dry ice/ dry ether Product
Options
- AEthanoic acid
- BPropanoic acid
- C2-Methylpropanoic acid
- DButanoic acid
Correct answer
B. Propanoic acid
Step-by-step solution
Grignard Reaction with Carbon Dioxide Ethylmagnesium bromide ( CH ₃ CH ₂ MgBr ) reacts as a nucleophile with carbon dioxide ( CO ₂ ) in dry ether, attacking the electrophilic carbon to form a magnesium carboxylate salt. CH ₃ CH ₂ MgBr + CO ₂ CH ₃ CH ₂ COO ⁻ Mg ⁺ Br Hydrolysis with dilute hydrochloric acid liberates the carboxylic acid. CH ₃ CH ₂ COO ⁻ Mg ⁺ Br + HCl CH ₃ CH ₂ COOH + MgBrCl The product is propanoic acid ( CH ₃ CH ₂ COOH ), corresponding to option B.