MHT CET202522 Apr 2025Evening ShiftChemistryCarboxylic Acid DerivativesActual
In a reaction, ( CH ₃ )₂ CHMgBr + CO ₂ [ ether ] dry A [ dil HCl ] H OH ~B . Find the product ' B ' of above reaction.
Options
- APropanoic acid
- B2-Methyl propanoic acid
- CButanoic acid
- D2,2-dimethyl ethanoic acid
Correct answer
B. 2-Methyl propanoic acid
Step-by-step solution
The Grignard reagent isopropyl magnesium bromide , ( CH ₃)₂ CHMgBr , undergoes carboxylation with CO ₂ in dry ether to form a magnesium carboxylate intermediate. ( CH ₃ )₂ CHMgBr + CO ₂ ( CH ₃ )₂ CHCOO ^- MgBr ^+ Hydrolysis with dilute HCl yields the carboxylic acid product. ( CH ₃ )₂ CHCOO ^- MgBr ^+ + H ₃ O ^+ ( CH ₃ )₂ CHCOOH + Mg ²⁺ + Br ^- + H ₂ O The IUPAC name of ( CH ₃)₂ CHCOOH is 2-methylpropanoic acid , corresponding to option B.