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MHT CET202120 Sep 2021Evening ShiftChemistryChemical EquilibriumActual

The pH of 0.1 M solution of monobasic acid is 2.34 . Calculate the degree of dissociation of the acid.

Options

  1. A3.1 10⁻²
  2. B4.5 10⁻²
  3. C2.18 10⁻²
  4. D2.5 10⁻³

Correct answer

B. 4.5 10⁻²

Step-by-step solution

pH =2.34, c =0.1 M (i) pH =- ₁₀ [ H ⁺ ] gathered ₁₀ [ H ⁺ ]=- pH =-2.34 =-2-0.34-1+1 =-3+0.66= 3 .66 gathered [ H ⁺ ]= antilog 3 .66 =4.571 10⁻³ ~mol dm ⁻³ (ii) [ H ⁺ ]= c = [ H ⁺ ] c = 4.571 10⁻³ 0.1 =4.571 10⁻²

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