What is the molar mass of third member of homologous series if the molar mass of first member is 46 g ?

Step-by-step solution

Two successive homologues differ by one - CH ₂ - (methylene) unit, i.e. by a molar mass of (12+2) g mol ⁻¹=14 ~g ~mol ⁻¹ . Molar mass of first member =46 ~g Molar mass of third member =46+14+14=74 ~g