A charcoal cube having side length (10 ~cm ) is chopped lengthwise into 5 equal pieces. Then the effective adsorption power

Step-by-step solution

Initial volume of cube (=(10)^3=1000 ~cm ^3 ) (V ) when cube is chopped along length then it will form cuboid in which length (=6 ~cm ) ( aligned breadth & =10 ~cm height & =10 ~cm aligned ) Adsorption power ( ) more surface area ( 6 ~cm ) ( 6 (10)^2 600 ~cm ^2 ) Final surface area of the cuboid ( aligned & =2(l b+b h+h l) Area of cuboid & =2(2 10+100+20) & =280 ~cm ^2 aligned ) For final cuboid area (=280 5=1400 ~cm ^2 ) So, final adsorption power ( 1400 ~cm ^2 ) ( aligned Final adsorption power Initial adsorption