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MHT CET202522 Apr 2025Evening ShiftChemistryRedox ReactionsActual

A compound of Xe and F is found to have atomic ratio Xe : F as 0 4: 2 4 , Find the oxidation number of Xe ?

Options

  1. A-4
  2. BZero
  3. C+4
  4. D+6

Correct answer

D. +6

Step-by-step solution

The atomic ratio Xe:F = 0.4:2.4 simplifies to 1:6 by dividing both values by 0.4 , giving the formula XeF ₆ . Since fluorine has oxidation state -1 and the compound is neutral, the oxidation number x of xenon satisfies: x + 6 (-1) = 0 x = +6 The oxidation number of Xe is +6 , corresponding to option D.

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