Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET20249 May 2024Morning ShiftChemistryRedox ReactionsActual

What is the value of x and y in order to balance following redox reaction? xCuO + yNH ₃ xCu + N ₂+ xH ₂ O

Options

  1. Ax =2, y =1
  2. Bx =1, y =2
  3. Cx=2, y=3
  4. Dx=2, y=3

Correct answer

C. x=2, y=3

Step-by-step solution

Reaction: x CuO +y NH ₃ x Cu + N ₂+x H ₂ O . Assign oxidation states: - Cu in CuO: +2 , reduced to 0 in Cu . - N in NH ₃:-3 , oxidized to 0 in N ₂ . Write half-reactions: 1. Reduction: Cu ²⁺+2 e⁻ Cu , - x CuO contributes 2 x electrons. 2. Oxidation: 2 NH ₃ ~N ₂+6 e⁻ , - Each y NH ₃ contributes 3 y electrons. Equate total electrons: 2 x=3 y x= 3 y 2 . Trial values to balance: Let x=2: y=3 . Balanced Equation: 2 CuO +3 NH ₃ 2 Cu + N ₂+3 H ₂ O Answer: x=2, y=3 , Option 3.

Practice Redox Reactions on Quantrex Academy →

More from Redox Reactions

x moles of K₂ Cr₂ O₇ oxidises 1 mole of ferrous oxalate, in acidic medium. Hence 'x' is: 2026In the redox reaction, taking place in acidic medium: X MnO ₄^- (aq) + Y SO ₂(g) Mn ⁺²(aq) + HSO ₄^- (aq) , the ratio of X:Y in a stoichiometrically balanced equation will be 2026In the reaction, Cr ₂ O ₇²⁻ + 4 H ₂ O ₂ + 2 H ^+ 2 CrO ₅ + H ₂ O The change in oxidation state of Cr is: 2026What are the numbers of protons ( H ^+ ) and electrons ( e ^- ), respectively, required for the reduction of [ Cr ₂ O ₇]²⁻ to Cr ³⁺ under an aqueous acidic condition? 2026Given below are two statements. Statement-I: In H ₂ O ₂ , each oxygen atom is assigned an oxidation number of -1 , in RbO ₂ each oxygen atom is assigned an oxidation number of - 1 2026a C ₂ O ₄²⁻ + b MnO ₄^- + c H ^+ x Mn ²⁺ + y H ₂ O + z CO ₂ a and x respectively are 2026What is the number of electrons gained by Cl atom when n mole of ClO ₄^- is transformed into n mole of ClO ₂^- ion? 2026What is the oxidation number of Cl in HOClO ₂ ? 2026 Full Redox Reactions list All MHT CET PYQs