Calculate the number of atoms present in 1 g metal that forms simple unit cell structure if product of density and volume of unit cell is 66.5 10⁻²⁴ g

Step-by-step solution

For a simple cubic unit cell, the number of atoms per unit cell is Z = 1 . The mass of one unit cell is equal to the product of its density and volume. Mass of one unit cell = V = 66.5 10⁻²⁴ g . Since there is 1 atom per unit cell, the mass of one atom is 66.5 10⁻²⁴ g . The number of atoms in 1 g of the metal is given by: Number of atoms = Total mass Mass of one atom Number of atoms = 1 66.5 10⁻²⁴ Number of atoms = 0.015037 10²⁴ Number of atoms 1.504 10²²