Calculate the number of atoms in 1 g metal that forms bcc crystal structure [ a^3 = 6 6 10⁻²² g ]

Step-by-step solution

The mass of one unit cell is given by the product of its density and volume: Mass of unit cell = a^3 = 6 6 10⁻²² g For a body-centered cubic (bcc) crystal structure, the number of atoms per unit cell is Z = 2 . Mass of one atom = Mass of unit cell Z = 6 6 10⁻²² 2 = 3 3 10⁻²² g The number of atoms in 1 g of the metal is: Number of atoms = 1 g Mass of one atom = 1 3 3 10⁻²² = 3 03 10²¹ Answer: 3 03 10²¹